Q:What is the direction of the force on a wire carrying a current due east in a

Question

Q:What is the direction of the force on a wire carrying a current due east in a location where the Earth

Q:What is the direction of the force on a wire carrying a current due east in a location where the Earth??s field is due north? Both are parallel to the ground. Direction of force is: Vertically up from groundYou are correct. Your receipt no. is 159-1759 Q:Calculate the force per meter if the wire carries 21.0 A and the field strength is 2.68 A ?10-5 T. Q:What diameter silver wire would have its weight supported by this force? Q:Calculate the resistance per meter and the voltage per meter needed. (You do not need to enter any units.) resistance per meter = voltage per meter needed = Answer remaining 3 questions and show work for points.

Explanation / Answer

B = magnetic field = 2.68 * 10-5

i = current = 21 A

a) magnetic force on current carrying wire is given as ::

Fb = i B L

so Fb / L = i B = 21 A * 2.68 * 10-5 = 56.28 x 10-5 N/m

b) density of silver = p = 10490 kg/m3

let the length of wire is L and radius be ''r''

so Volume of wire = V = pi r2 L

so mass = m = pV = 10490 * (3.14) r2 L =

weight of wire = mg = 10490 * (3.14) r2 Lg

weight of wire is supported by magnetic force

so weight = Fb

10490 * (3.14) r2 Lg = Fb

10490 * (3.14) r2 (9.8) = Fb/L

322798.3 r^2 = 56.28 x 10-5

r = 4.17 x 10-5

so diameter = d = 2r = 2 * 4.17 x 10-5 = 8.34 x 10-5 m

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