ON: BACK NEXT Question 10 A bowling ball encounters a 0.760-m vertical rise on t
ID: 1261142 • Letter: O
Question
Explanation / Answer
Note that for a solid ball,
I = 2/5 mR^2
By conservation of energy,
1/2 Iwi^2 + 1/2 m vi^2 = 1/2 Iwf^2 + 1/2 mvf^2 + mgh
As w = v/r
1/2 (2/5 mR^2)(vi/r)^2 + 1/2 m vi^2 = 1/2 (2/5 mR^2)(vf/r)^2 + 1/2 mvf^2 - mgh
0.6mvi^2 = 0.6mvf^2 + mgh
Thus,
vf^2 = vi^2 - gh/0.6
Solving for vf,
vf = 3.32 m/s [ANSWER]
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