A beam of unpolarized light of intensity I 0 passes through a series of ideal po

Question

A beam of unpolarized light of intensity I0 passes through a series of ideal polarizing filters with their polarizing directions turned to various angles as shown in the figure (Figure 1) . Assume that ? = 35.0?.

A. What is the light intensity (in terms of I0) at points A, B, and C?

B.If we remove the middle filter, what will be the light intensity at point C?

Answer in the order indicated. Separate your answers with commas. IAI0, IBI0, ICI0= A beam of unpolarized light of intensity I0 passes through a series of ideal polarizing filters with their polarizing directions turned to various angles as shown in the figure (Figure 1) . Assume that ? = 35.0?. A. What is the light intensity (in terms of I0) at points A, B, and C? Answer in the order indicated. Separate your answers with commas. IAI0, IBI0, ICI0= B.If we remove the middle filter, what will be the light intensity at point C?

Explanation / Answer

Malus Law for unpolarized light: I = Io/2

For polarized light: I = Io*[cos(theta)]^2

Thus: at A, the intensity will be: Io/2

at B, (theta = 35 degrees) the intensity will be: 0.3355*Io

at C, (theta w.r.t previous = 55 degrees) the intensity will be: 0.11*Io

If we remove the middle filter, theta becomes 90 degrees. Thus output intensity = 0.

Related Questions

Navigate

• Browse (All)
• Browse A
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.