particle having charge q = +2.30 ?C and mass m = 0.010 0 kg is connected to a st

Question

particle having charge q = +2.30 ?C and mass m = 0.010 0 kg is connected to a string that is L = 1.90 m long and tied to the pivot point P in the figure below. The particle, string, and pivot point all lie on a frictionless, horizontal table. The particle is released from rest when the string makes an angle ? = 60.0? with a uniform electric field of magnitude E = 250 V/m. Determine the speed of the particle when the string is parallel to the electric field.
m/s

particle having charge q = +2.30 ½C and mass m = 0.010 0 kg is connected to a string that is L = 1.90 m long and tied to the pivot point P in the figure below. The particle, string, and pivot point all lie on a frictionless, horizontal table. The particle is released from rest when the string makes an angle ? = 60.0½ with a uniform electric field of magnitude E = 250 V/m. Determine the speed of the particle when the string is parallel to the electric field.

Explanation / Answer

According to law of conservation of energy-

qEl(1-cos theta)=1/2mv2

v2=2qEl(1-cos theta)/m

v=0.33m/s.

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