A 1 170.0 kg car traveling initially with a speed of 25.000 m/s in an easterly d
ID: 1259874 • Letter: A
Question
A 1 170.0 kg car traveling initially with a speed of 25.000 m/s in an easterly direction crashes into the back of a 9 900.0 kg truck moving in the same direction at 20.000 m/s. The velocity of the car right after the collision is 18.000 m/s to the east.
A 1 170.0 kg car traveling initially with a speed of 25.000 m/s in an easterly direction crashes into the back of a 9 900.0 kg truck moving in the same direction at 20.000 m/s. The velocity of the car right after the collision is 18.000 m/s to the east. (b) What is the change in mechanical energy of the car??truck system in the collision? J (a) What is the velocity of the truck right after the collision? (Give your answer to five significant figures.)Explanation / Answer
Here , we will conservation of momentum
Using conservation of momentum
mc*Vci +mT*Vti = mc*Vcf + mT*Vtf
1170 * 25 + 9900 * 20 = 1190*20 + 9900 * Vtf
VTf = 20.55 m/s
the velocity of truck after the collision is 20.55 m/s
b)
Here , loss in mechanical energy = change in KE
change in Energy = 0.5 * 1170 * (20^2 - 25^2) + 0.5 *9900 * (20.55^2 - 20^2)
change in energy = -21227.6 J
the change in mechanical energy is -21227.6 J
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