P = ___ hp P=___KW Use the values from above to help you work this exercise. Sup

Question

P = ___ hp

P=___KW

Use the values from above to help you work this exercise. Suppose the same elevator car with the same load descends at 3.00 m/s. What minimum power is required? (Here, the motor removes energy from the elevator by not allowing it to fall freely.)
P = ______ kW
P = _____ hp

A 1.20 X 10^3 N retards its motion upward, as shown in the figure. What minimum power, in kilowatts and horsepower, must the motor deliver to lift the fully loaded elevator at a constant speed of 3.00 m/s? P = ___ hp P=___KW Use the values from above to help you work this exercise. Suppose the same elevator car with the same load descends at 3.00 m/s. What minimum power is required? (Here, the motor removes energy from the elevator by not allowing it to fall freely.) P = ______ kW P = _____ hp X 10^2 kg. A constant friction force of 3.94 X 10^3-kg elevator car carries a maximum load of 7.40

Explanation / Answer

The elevator cable must exert a force whose sum is equal to weight of the elevator + weight of the maximum load + friction

Therefore the total force the cable must exert in the upward direction = 23340 newtons

and the elevator must go up with a speed 3 m/s

Therefore, power in watts = 70020

= 70.02 kW

= 93.90 horsepower

While descending, friction would act in the upward direction and weight would act in the downward direction. Therefore the force which the cable needs to exert is 15460 newtons

And velocity is supposed to be downwards. THerefore, power will be negative

P = -46.38 kW

= -62.20 horsepower

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