need some help on this homework thanks As shown below, a square loop of wire of
ID: 1259823 • Letter: N
Question
need some help on this homework thanks
As shown below, a square loop of wire of side a moves through a uniform and constant magnetic field of magnitude B perpendicular to the page at constant velocity v directed to the right Judd says that the emf induced in the loop is zero. Roger claims that it has magnitude Blv. Which one, if either, is correct, and why? The diagram below show the position of a long straight wire perpendicular to the page and set of directions labeled A through H. 3.The path of a charged particle initially moving parallel to a uniform magnetic field will be a:Explanation / Answer
For part 1:
Emf is the change in magnetic flux and magnetic flux can be calculated by multiplying B*A.
It's the magnetic field multiplied by the area. The flux formula in this case does not use velocity, Also, since the area is not changing (since change in magnetic flux is BdA), the magnetic flux remains constant as well. Since emf is the change in magnetic flux and there is no change (it's constant), it is 0.
Part 2:
The other question is just the right hand rule. Since the current comes out of the page and the force is directed to the right, the magnetic field has to be going up at point C. It is tough to explain with the right hand rule without being there in person, but another way is to do a cross product of a vector using i,j and k. K is coming out of the page, i is going right and j is going up on the page.
Current is coming out of the page, so it just has the positive k direction. It has nothing going towards i or j.
The other vector points towards P. It has nothing going in the k direction on nothing in the j direction, it just goes right towards positive i. Cover up i to calculate i, it is 0. Cover up k to get k, it is zero. J is negative, but since the cross calculation is also negative it makes j positive. That is how the vector goes into the positive j direction, aka C in this case.
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