A teapot with a surface area of 845 cm 2 is to be plated with silver. It is atta

Question

A teapot with a surface area of 845 cm2 is to be plated with silver. It is attached to the negative electrode of an electrolytic cell containing silver nitrate (Ag+ NO3?). The cell is powered by a 12.0-V battery and has a resistance of 1.90 ?. If the density of silver is

A teapot with a surface area of 845 cm2 is to be plated with silver. It is attached to the negative electrode of an electrolytic cell containing silver nitrate (Ag+ NO3?). The cell is powered by a 12.0-V battery and has a resistance of 1.90 ?. If the density of silver is 1.05 X 10^4 kg/m3, over what time interval does a 0.133-mm layer of silver build up on the teapot? h

Explanation / Answer

Volume of silver = 500 cm2 x 0.0133 cm = 6.65 cm3

mass = 6.65 cm3 x 10.5 g/cm3   = 69.825 g

Number of atoms = number of charge = 69.825 g x (1mol/107.87g) x 6.022 x 1023 atoms/mol

= 3.898 x 1023 charges

total charge = 3.898 x 1023 charges x 1.602 x 10-19 C/charge

= 6.245 x 104 C

now Q/t = V/R

t = QR/V = 6.245 x 104 x 1.90 ohm/12 V

= 9887.9 sec = 2.75 hours

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