(a) What current flows? A (b) Calculate the power supplied to the bulb using I 2

Question

(a) What current flows?
A

(b) Calculate the power supplied to the bulb using I2Rbulb.
W

(c) Is this power the same as calculated using V2/Rbulb (where V is the voltage drop across the bulb)?

NoYes   

The hot resistance of a flashlight bulb is 2.00 Omega internal resistance. (a) What current flows? A (b) Calculate the power supplied to the bulb using I^2Rbulb. W (c) Is this power the same as calculated using V^2/Rbulb (where V is the voltage drop across the bulb)? NoYes Omega, and it is run by a 1.59 V alkaline cell having a 0.100

Explanation / Answer

1)current = V / Rnet = 1.59/(2 + 0.1) = 0.757 A

2) power = i^2R = 0.757^2 * 2.1 =1.20 Watt

3) power = 1.59^2 / 2.1 = 1.20 watt ..................so Yes

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