Problem 22.62 Two metal spheres each 1.4 c m in radius are far apart. The first
ID: 1259246 • Letter: P
Question
Problem 22.62 Two metal spheres each 1.4cm in radius are far apart. The first sphere carries 40nC of charge, the second -12nC . Part A What is the potential on each? Express your answer using two significant figures. V1,V2 = kV Part B If the spheres are connected by a thin wire, what will be the potential on each once equilibrium is reached? Express your answer using two significant figures. V? = kV on each spherePart C How much charge must move between the spheres in order to achieve equilibrium? Express your answer using two significant figures. ?Q= nC moves from the first sphere to the second Problem 22.62 Two metal spheres each 1.4cm in radius are far apart. The first sphere carries 40nC of charge, the second -12nC . Part A What is the potential on each? Express your answer using two significant figures. V1,V2 = kV Part B If the spheres are connected by a thin wire, what will be the potential on each once equilibrium is reached? Express your answer using two significant figures. V? = kV on each sphere
Part C How much charge must move between the spheres in order to achieve equilibrium? Express your answer using two significant figures. ?Q= nC moves from the first sphere to the second Problem 22.62 Problem 22.62 Two metal spheres each 1.4cm in radius are far apart. The first sphere carries 40nC of charge, the second -12nC . Two metal spheres each 1.4cm in radius are far apart. The first sphere carries 40nC of charge, the second -12nC . Two metal spheres each 1.4cm in radius are far apart. The first sphere carries 40nC of charge, the second -12nC . Part A What is the potential on each? Express your answer using two significant figures. V1,V2 = kV Part B If the spheres are connected by a thin wire, what will be the potential on each once equilibrium is reached? Express your answer using two significant figures. V? = kV on each sphere
Part C How much charge must move between the spheres in order to achieve equilibrium? Express your answer using two significant figures. ?Q= nC moves from the first sphere to the second Part A What is the potential on each? Express your answer using two significant figures. V1,V2 = kV Part A What is the potential on each? Express your answer using two significant figures. V1,V2 = kV V1,V2 = kV V1,V2 = kV Part B If the spheres are connected by a thin wire, what will be the potential on each once equilibrium is reached? Express your answer using two significant figures. V? = kV on each sphere
Part B If the spheres are connected by a thin wire, what will be the potential on each once equilibrium is reached? Express your answer using two significant figures. V? = kV on each sphere
V? = kV on each sphere V? = kV on each sphere
Part C How much charge must move between the spheres in order to achieve equilibrium? Express your answer using two significant figures. ?Q= nC moves from the first sphere to the second Part C How much charge must move between the spheres in order to achieve equilibrium? Express your answer using two significant figures. ?Q= nC moves from the first sphere to the second ?Q= nC moves from the first sphere to the second ?Q= nC moves from the first sphere to the second V1,V2 = kV
Explanation / Answer
A)
V1=Q/4*PI*EPSILON*R
=KQ/R
=9*109*40*10-9/1.4*10-2
=257.14*102v
V2=Q/4*PI*EPSILON*R
=KQ/R
=-9*109*12*10-9/1.4*10-2
=-77.14*102
B)
they are connected and are at equilibrium, the net charge will be zero hence charge at sphere 1 should be equal to charge at sphere 2
when they are connected, they'll quickly attain equilibrium- the potential difference across the wire will be zero, and the two spheres will carry the am charge. But it's not true that the net charge will be zero- net meaning the sum of the charges on the two spheres- and you've said that the charge on each sphere is a voltage!
C)
The point of the sentence "charge is conserved" is that the total (/net) charge is the same before and after you connect the two spheres- so all you're doing is redistributing it between the two of them, and what one loses the other must gain.
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