The Quality Control Department employs five technicians during the day shift. Li
ID: 1211008 • Letter: T
Question
The Quality Control Department employs five technicians during the day shift. Listed below is the number of times each technician instructed the production foreman to shut down the manufacturing process last week.
Technician Shutdowns
Taylor 6
Hurley 5
Gupta 7
Rousche 5
Huang 3
1. How many samples, without replacement of size two are possible?
2. Compute teh mean of the sample means and compare the population mean. (round your answers to 1 decimal place)
- The mean of the sample means is?
- The population mean is?
-Are both means equal or not equal. (PLEAE SHOW ALL STEPS)
Explanation / Answer
1. Two technicians can be selected from 5 technicians in C(5, 2) ways = 10 ways. Thus, 10 different samples of 2 technicians each are possible.
2. Let the 5 technicians be in the order of a, b, c, d, e . Means
Taylor (a)
Hurley (b)
Gupta (c)
Rousche (d)
Huang (e)
Mean number of shutdowns ordered = (n1 + n2)/2
(c) The mean of the sample means = Sum of the sample means/Number of samples
= 52/10 = 5.2 shutdowns
(d) Population mean = (6+5+7+5+3) / 5 = 26 / 5 = 5.2 shutdowns
(e) Mean of the sample means = Population mean.
sample ab ac ad ae bc bd be cd ce deMean number of shutdowns ordered = (n1 + n2)/2
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