need help asap thanks relief and gradient (slope) analysis LONG BEACH COMMIw Act
ID: 119574 • Letter: N
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need help asap thanks
relief and gradient (slope) analysis
LONG BEACH COMMIw Activity 5 Relief and Gradient (Slope) Analysis Name: Course/Section: Date: On a visit to Yosemite, you and some friends find a nice place along the Merced River for a picnic, You have a topographic contour map (Fig. A5.1) in which thindex contours are labeled in feet From your resting place at point A, you decode to gain a better vantage point by walking up to point B. 6600 6200 North Merced' River. A. 1000 feet Figure A5.1 A Using the labeled elevations of the index contours as your guide, what is the contour interal (the clevation difference ft between two adjacent contours) in Fig. A5.1? You have a bar scale on the map that indicates a distance of 1000 ft. on the ground in your pienic area. How long is that bar scale on the map in mm B using a metric ruler on the map, and then use your measurement of how many mm on the map equal 1000 ft. in the field to find the answer using proportions.) -ft. C What is the horizontal distance from A to B measured along a straight line in f? (Hint: Measure the disance from A to B D What is the average gradiens (elevation change divided by horizontal distance, both expressed in t.) along a straight line from A to B? 78Explanation / Answer
A. The contour values are 6200 and 6400 and we are having 4 contour in between hence the contour interval is:
=(6400-6200)/5
=200/5
=40
B. The scale given in figure gives a distance of 1000 feets on ground and is equivalent to 22 mm.
C. The horizontal distance between point A and B is:
=(47/22) x 1000 feets
= 2,136.36 feets
D. Gradient between point A and B is:
Elevation of B = 6600
Elevation of A = 6080
Difference in height = 6600-6080 = 520feets
Horizontal distance between point A and B is = 2,136.36 feets
Gradient = 2,136.36 feets/ 520feets = 4.108
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