Suppose an animal has a gene for coat color that is sex-linked (X-linkage) and i

Question

Suppose an animal has a gene for coat color that is sex-linked (X-linkage) and incompletely dominant, and in which females with an AA genotype have a black coat color; aa individuals have a yellow color; and those with Aa have marble coloration. If a marble female was crossed with a yellow male, then each of the following might result under normal Medelian conditions EXCEPT one. which one is the EXCEPTION?

A. Black male
B. Black female
C. Yellow male
D. Yellow female
E. Marble female

The answer is B, but can you please draw out the cross and explain! I though A could also be right?????

Explanation / Answer

the answer is b because of the fact that it is a sex linked trait. a male must have only one x chromosome so it may be black if it receives a single dominant gene on a single chromosme while a female must have two x chromosomes so can only be black if it reveives two dominant genes, one from each chromosome.

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