A study by the Information Technology department at WPU revealed company employe

Question

A study by the Information Technology department at WPU revealed company employees receive an average of four e-mails per hour. Assume the arrival of these e-mails is approximated by the Poisson distribution. (a) What is the probability , Prof. Smith, received exactly one e-mail between 4pm and 5pm yesterday? (b) What is the probability he did not receive any e-mail during this period? (c) What is the probability he received ten or more e-mails during the same period?

Explanation / Answer

this is fully solved and correct ., please do rate :) a) P (x =1) = e^-4 (4^1)/(1!) => 0.0732 b) P(x = 0) = e^-4 => 0.01832 c) Using normal approximation with mean = 4 , variance = 4, and continuity correction of 0.5 P (X>10) = P ( Z>(9.5-4)/2) => P (Z> 2.75) => 0.00298

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