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Table ES1 – Summary of Tsunami Model Results at Selected Locations Location Maxi

ID: 118123 • Letter: T

Question

Table ES1 – Summary of Tsunami Model Results at Selected Locations

Location

Maximum Water Level (m)

Maximum Drawdown of Water (m)

Maximum Water Flow Speed (m/s)

Tsunami Arrival Time (min)

Time to Maximum Water Level (min)

Port San Juan (entrance near Port Renfrew)

3.5

-1.0

0.7

35

50

Sooke Harbour (entrance)

2.5

-0.2

0.6

60

75

Q). Assume Port San Juan (entrance near Port Renfrew) and Sooke Harbour entrance are 58 km apart. Based this distance and data in Table ES1 (considered above), what is the average speed in km/hr of the tsunami wave traveling between these two points? This is just arithmetic but you must be careful with units. Distance is in km. Time difference from Table ES1 is in minutes, and we want wave speed in km/hr. __________ (ENTER VALUES ONLY, NO TEXT CHARACTERS.)

Location

Maximum Water Level (m)

Maximum Drawdown of Water (m)

Maximum Water Flow Speed (m/s)

Tsunami Arrival Time (min)

Time to Maximum Water Level (min)

Port San Juan (entrance near Port Renfrew)

3.5

-1.0

0.7

35

50

Sooke Harbour (entrance)

2.5

-0.2

0.6

60

75

Q). Assume Port San Juan (entrance near Port Renfrew) and Sooke Harbour entrance are 58 km apart. Based this distance and data in Table ES1 (considered above), what is the average speed in km/hr of the tsunami wave traveling between these two points? This is just arithmetic but you must be careful with units. Distance is in km. Time difference from Table ES1 is in minutes, and we want wave speed in km/hr. __________ (ENTER VALUES ONLY, NO TEXT CHARACTERS.)

Explanation / Answer

here tsunami arrival time of both the points are given in mins and distance is in km. sowe have toconvert the mins in to the hours :

port san juan : 0.58 hrs

sook harbour: 1 hr

now the distance between them is 58 km

port san juan : 58km/ 0.58 hrs = 100 km/hr

sook harbour: 58km/1 hr = 58 km/hr

The average speed is about = (100+58)/ 2 = 79 km/hr