A firm has two production plants where they produce the same product. The cost f
ID: 1181087 • Letter: A
Question
A firm has two production plants where they produce the same product. The cost function at plant #1 is (C_{1}(Q_{1})=10Q_{1}+.5Q_{1}) The cost function at plant #2 is (C_{2}(Q_{2})=10Q_{2}+2Q_{2}^{2})
A) If the firm wants to produce Q total units of output, what fraction of Q will be produced at plant #1? What fraction at plant #2? Show all work. B) What is the firms total cost function in terms of Q? Show all work. A) If the firm wants to produce Q total units of output, what fraction of Q will be produced at plant #1? What fraction at plant #2? Show all work. B) What is the firms total cost function in terms of Q? Show all work.Explanation / Answer
marginal cost of plant 1
MC(Q1)=d/dQ {C1(Q1)} = d/dQ (10Q1 + 0.5Q1)
MC(Q1)= d/dQ (10Q1 + 0.5Q1)
MC(Q1) = 10+0.5 = 10.5
marginal cost of plant 2
MC(Q2)=d/dQ {C2(Q2)} = d/dQ (10Q2 + 2(Q2)^2)
MC(Q2)= 10 + 4Q2
(a)
The plant 1 has a lower marginal cost with respect to plant 2, so it should distribute its production in such a way that MC1(Q1) = MC2(Q2) Because MC2 > MC1, this means that Q1 should be greater than Q2 in order for this equation to balance out.
here Q1+Q2 =Q
so ratio of quantitly produce by plant 1 and plant 2 are...
Q2/Q1 = MC1/MC2
Q2/Q1 = 10.5/(10 + 4Q2).......(1)
by solving eq 1
10Q2 +4(Q2)^2 = 10.5Q1
Q1 = [10Q2 +4(Q2)^2]/(10.5)
Q1 = 0.95Q2+0.38(Q2)^2
Q= Q1+Q2
put the value of Q1
Q= 0.95Q2+0.38(Q2)^2+Q2
Q= 1.95Q2+0.38(Q2)^2
using quarditic equation formula
Q2 = {-1.95+sqrt[(3.8)-1.52Q]}/0.76
Q2 = {-1.95-sqrt[(3.8)-1.52Q]}/0.76
and Q1= Q-Q2
so the fraction of Q will be produced at plant #2
Q2 = {-1.95+sqrt[(3.8)-1.52Q]}/0.76
and
the fraction of Q will be produced at plant #1
(b)
for firms total cost function in terms of Q
put the value of Q1 or Q2 in terms of Q in cost equation we can find total cost equation.
thnq
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