10.61 The per-store daily customer count (i.e., the mean number of customers in
ID: 1177915 • Letter: 1
Question
10.61 The per-store daily customer count (i.e., the mean number of customers in a store in one day) for a nationwide convenience store chain that operates nearly 10,000 stores has been steady, at 900, for some time. To increase the customer count, the chain is considering cutting prices for coffee beverages. The question to be determined is how much to cut prices to increase the daily customer count without reducing the gross margin on coffee sales too much. You decide to carry out an experiment in a sample of 24 stores where customer counts have been running almost exactly at the national average of 900. In 6 of the stores, the price of a small coffee will now be $0.59, in 6 stores the price of a small coffee will now be $0.69, in 6 stores, the price of a small coffee will now be $0.79, and in 6 stores, the price of a small coffee will now be $0.89. After four weeks of
selling the coffee at the new price, the daily customer count in the stores was recorded and stored in .
a. At the 0.05 level of significance, is there evidence of a difference in the daily customer count based on the price of a small coffee?
Explanation / Answer
Yes, the program I have does not explain everything. I do not think I could transfer the output from excel and paste it here.
H0: No difference in average amount of work done by A,B, and C
Ha : Not all of them are the same.
Group 1 no of cases 5 mean 9.2
Group 2 no of cases 5 mean 11.6
Group 3 no of cases 5 mean 11.4
Grand mean 10.7333
Total sum of squares 42.9333
Between ss17.7333 Mean square 8.8667 deg of freedom 2
Within ss 25.2 Mean square 2.1 deg of freedom 12
F (2,12) = 4.2222
Critical F with .05 level from F-table = 3.8853
Calculated F exceeds critical F, so reject H0.
Evidence provides sufficient reason to reject the claim that there is no difference in the amount of work done by the three workers.
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