MULTIPLE CHOICE·Choose the one alternative that best completes the statement or

Question

MULTIPLE CHOICE·Choose the one alternative that best completes the statement or answers the question. 17) Suppose a random sample of n measurements is selected from a binomial population with 17) probability of success p 32. Given n 400, describe the shape, and find the mean and the standard deviation of the sampling distribution of the sample proportion, p. A) approximately normal; 0.32,0.0005 C) approximately normal; 0.32,0.023 B) skewed right; 0.32, 0.023 D) skewed right; 128, 9.33 18) What is the confidence level of the following confidence interval for ?? 18) A) 99% B) 98% C) 95% D) 90%

Explanation / Answer

Answer

17)

correct answer is (d)

For binomial distribution

mean = np

Here n= 400 and p =0.32

So mean = 32*4 = 128

Variance = np(1-p)

= 400*0.32*0.68 = 87.04

Hence standard daviation = 9.33

For binomial to be normal (approximate) p must be close to 0.5 but here it is 0.32 hence This is not approximate normal and it is right skewed.

18)

The correct option is b) 98%

Z value at -2.33 =.00990

Area between -2.33 and 2.33 = 1 - 2*0.0099 = 0.98

Hence confidance level is 98%

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