Question 2: A gas well is completed at a depth of 8,550 feet The log analysis sh
ID: 115788 • Letter: Q
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Question 2: A gas well is completed at a depth of 8,550 feet The log analysis showed total formation thickness of 12 feet of 16% porosity and 30% water saturation. On potential test, the well-produced dry gas with a specific gravity of 0.75. The reservoir pressure was determined from a drill stem test (DST) to be 3,850 psi and the log heading showed a reservoir temperature of 155° F. The gas will be produced at the surface where the standard pressure is 14.65 psi and the standard temperature is 60° F. The study of the offset wells producing from the same formation has shown that the wells are capable of draining 160 acres at a recovery factor of 85%. Compute the GIIP and the recoverable gas reserves. The gas formation volume factor is 259.89 Scf/CF. Question 3: In Question 2, the abandonment pressure has been determined to be 800 psi below which no gas could be economically produced. Based on this information, compute the ultimate gas recovery and the recovery factor. The formation volume factor at abandonment pressure is 51.88 Scf/CF.Explanation / Answer
Q. 2) here, we have to calculate two things GIIP and recoverable gas reserves.
Let's find out GIIP first,
Gas initially in place(GIIP) is the total amount of gas present in reservoir.
To calculate GIIP, we have formula that is
= (43560 x area x net pay thickness x porosity x (1 - water saturation)) / gas formation volume factor x recovery factor
= (43560 x 160 x 12 x 16 x (1 - 30)) / 259.89 x 85............. Equ 1
But here we need everything in decimal except recovery factor, area, net pay thickness
Hence, equation 1 becomes
= (43560 x 160 x 12 x 0.16 x ( 1 - 0.30))/259.89 x 85
= (13381632 x ( 0.70))/ 22090.65
= (9367142.4) / 22090.65
= 424.031 standard cubic feet(scf)
Now let's find out recoverable gas reserves
= GIIP x recovery factor
= 424.031 x 85
= 20,572.635 standard cubic feet (scf)
Q. 3) ?
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