dit View History Bookmarks Window Help Aplia: Student Question Amy is a hard-wor
ID: 1148581 • Letter: D
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dit View History Bookmarks Window Help Aplia: Student Question Amy is a hard-working college sophomore. One Tuesday, she decides to work nonstop until she has answered 250 practice probilems for her math course. She starts work at 8:00 AM and uses a table to keep track of her progress throughout the day. She notices that as she gets tired, it takes her onger to solve each problem. Time 8:00 AM 9:00 AM 10:00 AM 11:00 AM Noon Total Problems Answered 100 175 225 250 use the table to answer the flowig question The marginal, or additional, gain from Amy's second hour of work, from 9:00 AM to 10:00 AM, is The marginal gain from Amy's fourth hour of work, from 13:00 AM to noon, is Later, the teaching assistant in Amy's math course gives her some advice. "Based on past experience," the teaching assistant says, "working on 87.5 problems raises a student's exam score by about the same amount as reading the textbook for 1 hour" For simplicity, assume students always cover the same number of pages during each hour they spend reading this information, in order to use her 4 hours of study time to get the best exam score possibie, how many hours should she have spent working on problems, and how many should she have spent reading?Explanation / Answer
1) Marginal gain from 9 am to 10 am = 175 - 100 = 75 problems
2) Marginal gain from 11 am to noon = 250 - 225 = 25 problems
3) If Student spend all 4hrs on reading then his score will be 87.5 x 4 = 350
If student spend 1 hr working and 3 hours reading then problems solved = 100 + 3 x 87.5 = 362.5
If student spend 2 hr working and 2 hours reading then problems solved = 175 + 2 x 87.5 = 350
If student spend 3 hr working and 1 hours reading then problems solved = 225 + 1 x 87.5 = 312.5
Answer is b) 1 hour working and 3 hours reading
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