2:20 AM people.ucsc.edu iPad 2. Here we\'re going to consider a simplified solar
ID: 114178 • Letter: 2
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2:20 AM people.ucsc.edu iPad 2. Here we're going to consider a simplified solar system which consists of three components: hydrogen (H2), ice (H20) and silicate (MgSiO) For every 106 Si or Mg atoms, there are 2.1x10 O atoms available a) For every 10" silicate molecules produced, how many O atoms are left over? (1) b) Assume that all these remaining O atoms are converted into H20 molecules (hydrogen is effectively unlimited). How many H20 molecules are generated? (1) c) What is the ratio of the mass of H20 molecules to the mass of silicate molecules produced? Atomic weights are: H-1, 0-16, Mg 24, Si-28. (3) d) Explain why your answer to c) is consistent with the fact that the outer solar system contains larger planets than the inner solar system. (3) e) The mass of H2 in the initial solar nebula was about 300 times the mass of the silicates. If the mass of silicates in the present-day solar system is about 15 Earth masses, what mass of H2 was present in the initial solar system? What fraction of the present-day mass of the Sun (2x1030 kg) is this? (2)Explanation / Answer
a) for 106 Si atoms we need 3*106 O atoms, so remaining are,
2.1*107 - 3*106 = 1.8*107 O atoms remaining.
b) If all the O atoms are converted to H2O then there will be 1.8*107 H2O atoms as there is only 1 O in each H2O atom
c) H2O = 1+1+16 = 18
MgSiO3 = 24+28+16+16+16 = 100
H2O : MgSiO3 : 18:100
= 9:50 =0.18
d) The outter solar system contains bigger planets because they contain biffer compunds like silicates which have higher molecular weight. So, as the mass ratio suggests the planets are larger on outter solar system.
e) MassHydrogen = 300 * Masssilicate
Masssilicate= 15 Earth masses
MassHydrogen = 4500 Earth masses (15*300)
Masssun = 333,000 Earth masses
so it is 4500/333000 = 1.3513% i.e 0.013513
Please ask the rest of the questions in separate questionnaire.
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