Use the following Stata output for questions 4-13. It provides results for the f
ID: 1104878 • Letter: U
Question
Use the following Stata output for questions 4-13. It provides results for the following model, where college GPA is a function of age, high school GPA, average # of lectures missed per week, and average # of days per week the respondent drinks alcohol. colGPA-A. + ,age + .hsG PA + ,skipped + ,alcohol + u . reg colGPA age hsGPA skipped alcohol SourceI df MS Number of obs F( 4,136) 10.82 Prob > F R-squared Adj R-squared - 0.2191 Root MSE 141 Model 4.6852075 41.17130188 Residual 14.7208919 136 108241853 -0.0000 -0.2414 Total 19.4060994 140 138614996 329 colGPA I Coef Std. Err (95% C nf. Interval ] age 0206971 hsGPA 4831788 0.91 0.365-.0243449 3040221 0227765 657391 6623355 skipped I -.0894810273482-3.27 0.001 -.1435636 .0353983 alcohol.0341593 0214918 cons1.011975 -6383363 -.0083421 -.2503741 0766607 2.274323 . test age alcohol 1) age 0 2) alcohol-0 F 2, 136) 1.68 Prob>F 0.1910 . lincom age-alcohol 1) age alcohol-0 COlGPAI Coef Std. Err (95% conf. Interval] (1).0134622 031316-0.43 0.668 - .0753914 048467 t-ratio for the coefficient on alcohol? 4. What is the missing a. 0.98 b. 1.19 c. 1.59 d. 2.37 e. None of the above . Using the statistical table, the p-value for the coefficient on alcohol is a. approximately.02 b. approximately.06 c. approximately .11Explanation / Answer
4) t calue is calculated as follows t = coeff/ Standard error
t = 0.341593/ 0.214918
t= 1.59
Answer is d.
5) The p-value is the probability for a given statistical model that, when the null hypothesisis true, the statistical summary would be the same as or of greater magnitude than the actual observed results. The smaller the p-value, the larger the significance because it Indicates that the hypothesis under consideration may not adequately explain the observation. The p value here is 0.11 (c). Thus the large p value gives evidence of not rejecting the hypothesis in this case.
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