One of the possible compositions for nail polish remover is a solution containin
ID: 1090270 • Letter: O
Question
One of the possible compositions for nail polish remover is a solution containing water (15.0 % by volume), glycerol (10.0 % by volume), and acetone. Consider this solution (which has a density of 0.864 g/mL) for the next five problems. The densities of water (18.0 g/mol), glycerol (92.1 g/mol), and acetone (58.1 g/mol) are 1.00 g/mL, 1.26 g/mL, and 0.784 g/mL respectively. Hint: for the last three problems perform your calculations for 1000. mL of the solution. 16. (3) What is the volume percent of acetone in this solution? 17. (5) What is the weight of acetone contained in 100. mL of this solution? 18, (5) what is % (w/w) or the weight percent of acetone in this solution?Explanation / Answer
Ans. #16. Volume % of acetone = 100 % - Volume % of (water + glycerol)
= 100 % - (15.0 % + 10.0 %)
= 75.0 %
#17. We have, % volume of acetone in solution = 75.0 % (from #16).
A 75% (v/v) acetone means there is 75.0 mL acetone per 100.0 mL of solution.
So,
Volume of acetone in 00 mL solution = 75.0 % (v/v) x 100.0 mL = 75.0 mL
Now,
Mass of acetone = Volume x Density
= 75.0 mL x (0.784 g/ mL)
= 58.8 g
#18. Calculations per 1000.0 mL solution.
# Volume of acetone = 75%(v/v) x 1000.0 mL = 750 mL
Mass of acetone = 750.0 mL x (0.784 g/ mL) = 588.0 g
# Mass of 1000.0 mL solution = 1000.0 mL x (0.864 g/ mL) = 864.0 g
Now,
% acetone (w/w) = (mass of acetone/ mass of solution) x 100
= (588.0 g / 864.0 g) x 100
= 68.06 %
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