- University of Arizona CHEM 1 X C Home | Chogg.com - a X A Sapling Learning CHE
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- University of Arizona CHEM 1 X C Home | Chogg.com - a X A Sapling Learning CHEM 152X () C A i www.saplinglearning.com/ibiscms/mod/ibis/view.php?id=1816853 O 1198 | - O A Q Search O = a Sapling Learning Jump to... mermillar learning View Profile Logout Attempts Score O Gradebook O Assignment Ir O 2/23/2018 11:55 PM A 66.2/100 G 2/23/2018 04:35 PM A Print calculator La Periodic Table Qestion 19 af 20 6 2 90 Man A 7 1 100 Consider this reaction data: If you were going to graphically determine the activation energy of this reaction, what points would you plot? Available from: 2/15/2018 06:00 PM Due Date: 2/23/2018 11:55 PM Points Possible: 100 Grade Category: Homework Description: 8 2 A products Nurriter Number 9 1 TEK) kis') point 1: Policies: HW_F15 10 3 225 0.370 875 0.897 To avoid rounding errors, use at least three significant figures in all values. Number Number 11 1 point 2. 120 130 F E E = 5 You can check your answers, You can view solutions after you complete the assignment. You have three attempts per question. You lose 10% of the points available to each answer in your question for each incorrect attempt at that answer. 8 & 9 • • • • & Determine the rise, run, and slope of the line formed by these points. rise run slope Number Number Number 14 O elextbook 15 O 16 2 What is the activation energy of this reaction? OHelp With This Topic 17 3 Number o Web Help & Videos 18 1 100 J/mol 1900 O Technical Support and Bug Reports O Pravius Q Chek Ansar ES Y Hint 20 1100 www.saplinglearningcom/ithischis/user/view.php?id-1905274&course-74696; DO L A O O A DO 2 1 uS 223/2018 - ENG 10x57 PM =Explanation / Answer
here graph is drawn between ln K and 1/T
lnK = y -axis
1/T = x - axis
point 1: x = 4.44 x 10^-3 , y = -0.970
point 2 : x = 1.14 x 10^-3 , y = -0.109
rise = y2-y1 = 0.861
run = x2 - x1 = - 3.30 x 10^-3
slope = rise / run = - 0.861 / 3.30 x 10^-3 = -261
-Ea / R = slop
Ea = 261 x 8.314 = 2169 J / mol = actiavation energy
actiavation energy = 2.17 x 10^3 J/mol
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