l otebook. Calculate the amount of water lost and then the percent of water in t

Question

l otebook. Calculate the amount of water lost and then the percent of water in the hydrate. Check this result with instructor before you leave the lab. Place the dehydrated salt in the designated recovery beaker in the waste hood. Problems to be answered in your report 1. What mass of water is driven off when 12.52 g of SrCh.6H20 is heated? 2. The mineral gypsum contains 20.91 % water and 79.09 % CaSO4, what is the simplest empirical formula for gypsum? 3. 1.500 g of Na2S203.XH20 was heated until all the water was removed. Calculate the percent water of hydration and the formula of the hydrate if the residue after heating weighed 0.956 g. pow

Explanation / Answer

1) First we need to find the percentage of water in SrCl2•6H2O using the following formula:

% H2O = [(6 H2O)(100)] / (SrCl2•6H2O)

calculating total mass of water in SrCl2•6H2O
12 × H = 12 × 1.008 = 12.096
6 × O = 6 × 15.999 = 95.994
--------------------------------------...
Total water mass = 108.09 g

1 × Sr = 1 × 87.62 = 87.62
2 × Cl = 2 × 35.453
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Total mass of srcl2= 123.073 g

molar mass of SrCl2•6H2O = 231.163 g

% H2O = [(108.09)(100)] / (231.163)
% H2O = 46.759213%

Next, we need to take 46.759213% of 1.252 g of strontium hexahydrate:

mass of water driven off = (1.252 g)(46.759213) /100= 0.5854253 g or 0.5854 g

Answer: The mass of water driven off when 1.252 grams of SrCl2•6H2O is decomposed by heating is 0.5854 grams.

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