1. Write the balanced net ionic equation for the reaction of copper(II) with hyd
ID: 1088122 • Letter: 1
Question
1. Write the balanced net ionic equation for the reaction of copper(II) with hydroxide to form a complex ion.2. Draw the chemical structure of DMG in the space below. How does nickel(II) interact with this molecule?
3. Draw the structure of the hexacyanoferrate(II) complex ion in the space below.
4. The concentration of sulfide anions varies with the solution pH. Carefully explain this observation, including the role of Le Châtelier’s principle. Do you expect the sulfide concentration to be highest at low, high, or neutral pH? Why? 1. Write the balanced net ionic equation for the reaction of copper(II) with hydroxide to form a complex ion.
2. Draw the chemical structure of DMG in the space below. How does nickel(II) interact with this molecule?
3. Draw the structure of the hexacyanoferrate(II) complex ion in the space below.
4. The concentration of sulfide anions varies with the solution pH. Carefully explain this observation, including the role of Le Châtelier’s principle. Do you expect the sulfide concentration to be highest at low, high, or neutral pH? Why? 1. Write the balanced net ionic equation for the reaction of copper(II) with hydroxide to form a complex ion.
2. Draw the chemical structure of DMG in the space below. How does nickel(II) interact with this molecule?
3. Draw the structure of the hexacyanoferrate(II) complex ion in the space below.
4. The concentration of sulfide anions varies with the solution pH. Carefully explain this observation, including the role of Le Châtelier’s principle. Do you expect the sulfide concentration to be highest at low, high, or neutral pH? Why?
Explanation / Answer
1) the balanced net ionic equation for the reaction of copper(II) with hydroxide to form a complex ion :
The reaction of Co2+ with OH- led to formation of precipitate of Co(OH)2
Co2+ (aq) + 2 OH- (aq) -------------------> Co(OH)2 (s)
then Co(OH)2 (s) with access OH- led to formation of complex ion that is
Co(OH)2 (s) + 2 OH- (aq) ------------> Co(OH)4^2- (aq)
thus the complex ions is Co(OH)4^2- .
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