1. In Part 1A of the experiment, your first mixture (Mixture I) will be made fro
ID: 1087940 • Letter: 1
Question
1. In Part 1A of the experiment, your first mixture (Mixture I) will be made from the following reactants, with water as the solvent:
10.0 mL 4.0 M acetone + 10.0 mL 1.0 M HCl + 10.0 mL 0.0050 M I2 + 20.0 mL H2O
Use the dilution formula (C1V1 = C2V2) to calculate the initial concentrations of acetone, H+ (from HCl), and iodine (I2)
[acetone] ________ M ; [H+] _______M; [I2] _______M
2. Using the reaction mixture in Problem 1, a student found that it took 320 seconds for the color of the I2 to disappear. Remember: initial means the initial concentration of a component in the mixture at the start of the reaction.
a. What was the rate of the reaction?
b. Write the rate law for the reaction as it would apply to the mixture. (Fill in numbers and units for the rate and concentrations of each reactant). Rate = _________
c. What are the unknowns that remain in the equation in Part b?
3. How could you experimentally double the molarity of the acetone in the reaction mixture, keeping the total volume at 50 mL and keeping the same concentrations of H+ ion and I2 as in the original mixture?
4. A second reaction mixture (Mixture II) was made up in the following way: 20.0 mL 4.0 M acetone + 10.0 mL 1.0 M HCl + 10.0 mL 0.0050 M I2 + 10.0 mL H2O
a. What are the new initial concentrations of acetone, H+ ion, and I2 in this second reaction mixture? [acetone] _______M; [H+] _______M; [I2]_______ M
b. It took 125 seconds for the I2 color to disappear from the reaction mixture when it occurred at the same temperature as the reaction in Problem 2. What was the rate of the reaction? Rate = ______________
c. Write the rate law as it would apply to the Mixture II. (Fill in numbers and units for the rate and concentrations of each reactant).
5. Determine the order with respect to acetone (m), showing all your work. Round off the value of m to the nearest integer.
Explanation / Answer
I have solved the Q1 with multiple sub-parts as per Chegg guidelines, post multiple question to get the remaining answers
Q1)
Mixture Contains
10 mL of 4M acetone
10 mL of 1M HCl
10 mL of 0.0050M I2
20 mL of H2O
Molarity of acetone = Volume of acetone/(Total volume of solution) * Molarity of original acetone solution
=> 10/(10+10+20+10) * 4M
=> 0.8M
Molarity of H+= Volume of HCl/(Total volume of solution) * Molarity of original HCl solution
Molarity of HCl = Molarity of H+ (since HCl is a very strong acid solution)
=> 10/(10+10+20+10) * 1M
=> 0.2M
Molarity of I2 = Volume of I2 /(Total volume of solution) * Molarity of original I2 solution
=> 10/(10+10+20+10) * 0.0050M
=> 0.0010M
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