Imagine you have 350 grams of hot water that is 80 degree Celsius and you want t

Question

Imagine you have 350 grams of hot water that is 80 degree Celsius and you want to cool it to 25 degree Celsius. How many grams of -10 degree Celsius do you need to add to the hot water? Imagine you have 350 grams of hot water that is 80 degree Celsius and you want to cool it to 25 degree Celsius. How many grams of -10 degree Celsius do you need to add to the hot water? Imagine you have 350 grams of hot water that is 80 degree Celsius and you want to cool it to 25 degree Celsius. How many grams of -10 degree Celsius do you need to add to the hot water?

Explanation / Answer

Hot water (at 80 oC) ---> water (at 25 oC)

heat lost = mCpdT

m = 350 g

Cp = 4.18 J/g.oC

dT = (25 - 80) oC

So,

heat lost by hot water = 350 x 4.18 (25 - 80) = -80465 J

Heat gained by cold water (at -10 oC) = 80465 J = mCpdT

80465 = mass of cold water x 4.18 (25 - (-10))

mass of cold water = 550 g

So, the mass of cold water that needs to be added to the hot water would be 550 g        

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