1. The following results were collected for two experiments involving the reacti
ID: 1087446 • Letter: 1
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1. The following results were collected for two experiments involving the reaction at 600 oC between gaseous sulfur dioxide and oxygen to from gaseous sulfur trioxide. Experiment 1 Experiment 2 Initial Equilibrium Initial Equilibrium [SO2]o = 2.00 M [SO2] = 1.50 M [SO2]o = 0.500 M [SO2] = 0.590 M [O2]o = 1.50 M [O2] = 1.25 M [O2]o = 0 M [O2] = 0.0450 M [SO3]o = 3.00 M [SO3] = 3.50 M [SO3]o = 0.350M [SO3] = 0.260 M a. Write the balanced chemical equation. b. Write the mass action expression. c. Calculate the equilibrium constant for each experiment. Comment on your results. What will cause a change in the equilibrium constant? 1. The following results were collected for two experiments involving the reaction at 600 oC between gaseous sulfur dioxide and oxygen to from gaseous sulfur trioxide. Experiment 1 Experiment 2 Initial Equilibrium Initial Equilibrium [SO2]o = 2.00 M [SO2] = 1.50 M [SO2]o = 0.500 M [SO2] = 0.590 M [O2]o = 1.50 M [O2] = 1.25 M [O2]o = 0 M [O2] = 0.0450 M [SO3]o = 3.00 M [SO3] = 3.50 M [SO3]o = 0.350M [SO3] = 0.260 M a. Write the balanced chemical equation. b. Write the mass action expression. c. Calculate the equilibrium constant for each experiment. Comment on your results. What will cause a change in the equilibrium constant? 1. The following results were collected for two experiments involving the reaction at 600 oC between gaseous sulfur dioxide and oxygen to from gaseous sulfur trioxide. Experiment 1 Experiment 2 Initial Equilibrium Initial Equilibrium [SO2]o = 2.00 M [SO2] = 1.50 M [SO2]o = 0.500 M [SO2] = 0.590 M [O2]o = 1.50 M [O2] = 1.25 M [O2]o = 0 M [O2] = 0.0450 M [SO3]o = 3.00 M [SO3] = 3.50 M [SO3]o = 0.350M [SO3] = 0.260 M a. Write the balanced chemical equation. b. Write the mass action expression. c. Calculate the equilibrium constant for each experiment. Comment on your results. What will cause a change in the equilibrium constant? 1. The following results were collected for two experiments involving the reaction at 600 oC between gaseous sulfur dioxide and oxygen to from gaseous sulfur trioxide. Experiment 1 Experiment 2 Initial Equilibrium Initial Equilibrium [SO2]o = 2.00 M [SO2] = 1.50 M [SO2]o = 0.500 M [SO2] = 0.590 M [O2]o = 1.50 M [O2] = 1.25 M [O2]o = 0 M [O2] = 0.0450 M [SO3]o = 3.00 M [SO3] = 3.50 M [SO3]o = 0.350M [SO3] = 0.260 M a. Write the balanced chemical equation. b. Write the mass action expression. c. Calculate the equilibrium constant for each experiment. Comment on your results. What will cause a change in the equilibrium constant?Explanation / Answer
A. balanced equation
2SO+O2 ---------> 2SO3
B. Mass action expression = product concentration/reactant concentration
= [SO3]2/[SO2]2[O2]
C.Kequ1 = [3]2/[2]2[1.5]=1.5
K2 = [3.5]2/[1.5]2[1.25] = 4.3
K3 = [0.35]2/[0.5][0] = 0.12
k4 = [0.26]2/[0.59]2[0.045] = 4.50
C. When Kequ is larger than 1 it would means that the equilibrium is starting to favour the product
When Kequ is less thn 1 the reaction is reactant favored at equlibrium.
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