Write the chemical equation and the K a expression for the acid dissociation of

Question

Write the chemical equation and the Ka expression for the acid dissociation of each of the following acids in aqueous solution. First show the reaction with H+(aq) as a product and then with the hydronium ion. (Use the lowest possible coefficients. Omit states-of-matter in your answer.)

Part 1:

(a)    C6H5CO2H
Chemical equation with H+ as a product:

(b)Corresponding Ka expression:

(c)Chemical equation with hydronium ion as a product:

(d)Corresponding Ka expression:

Part 2:

(a)    HCO3-
Chemical equation with H+(aq) as a product:

(b)Corresponding Ka expression:

(c)Chemical equation with hydronium ion as a product:

(d)Corresponding Ka expression:

Thank You!!

Explanation / Answer

part 1

(a)    C6H5CO2H ----> C6H5CO2^- + H^+

b)   Ka = [C6H5CO2^-][H+]/[C6H5CO2H]

c) C6H5CO2H + H2O ----> C6H5CO2^- + H3O^+

H3O^+ = hydronium ion

d) Ka = [C6H5CO2^-][H3o+]/[C6H5CO2H]

part 2

a) HCO3-   ----> H+ + CO3^2-

b) Ka = [H+][CO3-2]/[HCO3-]

C) HCO3- + H2O ----> H3O+ + CO3^2-

d) Ka = [H3o+][CO3-2]/[HCO3-]

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