saplinglearning.com Part 2 ge, Alexandria - CHM 111 -Spring18-AHMAD: Chapter 3 P

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saplinglearning.com Part 2 ge, Alexandria - CHM 111 -Spring18-AHMAD: Chapter 3 Practice What is The Concentra Jump to... ginia Community College, Alexandria-CHM 111-Spring18-AHMAD Activities and Due D ates Chapter 3 Practice-Part 2 o 2/19/2018 12:00 AM 04/52/18/2018 09:19 PM Print CalculatorPeriodic Table Gradebook Question 10 of 11 Map Sapling Learning 69.0 mL of a 1.20 M solution is diluted to a total volume of 218 mL A 109-mL portion of that solution is diluted by adding 131 mL of water. What is the final concentration? Assume the volumes are additive. Number Check Answer ONet tl Exit Previous Give up & View Souton

Explanation / Answer

find the concentration after 1st dilution
use dilution formula
M1*V1 = M2*V2
1---> is for stock solution
2---> is for diluted solution

Given:
M1 = 1.2 M
V1 = 69.0 mL
V2 = 218.0 mL

use:
M1*V1 = M2*V2
M2 = (M1*V1)/V2
M2 = (1.2*69)/218
M2 = 0.3798 M

Now find the concentration after 2nd dilution:
use dilution formula
M1*V1 = M2*V2
1---> is for stock solution
2---> is for diluted solution

Given:
M1 = 0.3798 M
V1 = 109 mL
V2 = 109 + 131 = 240 mL

use:
M1*V1 = M2*V2
M2 = (M1*V1)/V2
M2 = (0.3798*109)/240
M2 = 0.1725 M
Answer: 0.1725 M

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