ta/Observations py the following table into your lab report. Mass of green salt

Question

ta/Observations py the following table into your lab report. Mass of green salt sample i, volume of NaOH required to reach 1st endpoint 0.1v2 f required to reach 2" endpoint C Tot vol to cndoin V. tandardized molarity of NaOH (given) ulations/Results ulations for K: Show a labeled sample calculation for each. 0.0999 Determine, to the nearest 0.01 mL, the volume (Vi) of NaOH needed to neutralize the H' fr Excel graph. This is the endpoint volume of the H titration. Calculate the number of moles of H' neutralized in the eluted solution. Calculate the number of moles of K' present in the green salt sample used Calculate the mass of Kt in the green salt sample. Calculate the % of K+ in the green salt.(% mass = (mass ofcomponent/mass of compound) x aholod samnle calculation for each.

Explanation / Answer

as per the calculation first endpoint

Volume of NaOH = 10.50ml

molarity of NaOH = 0.0999

Moles of NaOH = 10.50*0.0999/1000 = 1.04895 *10-3

as one mole NaOH neutralises one mole H+

then moles of H+ = 1.04895 *10-3

and moles of K+ = 1.04895 *10-3 ( as each moles of K+ passed into the column one mole of H+ elutes)

= 1.04895 *10-3 *39 =0.04 g

% K+ = 0.04*100/0.162

= 25.25 %

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