If 25.0 g of NaCl is dissolved in water to a final volume of 50.0 mL, what is th

Question

If 25.0 g of NaCl is dissolved in water to a final volume of 50.0 mL, what is the ionic molarity of this solution? In other words, what is the molarity of this solution in terms of the number of moles of ions per liter of solution? Pre-lab Questions 1) If 25.0 g of NaCI is dissolved in water to a final volume of 50.0 mL, what is the ionic molarity of this solution? In other words, what is the molarity of this solution in terms of the number of moles of ions per liter of solution? Show your work. (1 pt)

Explanation / Answer

Answer

17.11M

Explanation

Mass of NaCl = 25g

Molar mass of NaCl = 58.44g/mol

No of moles of NaCl = 25g/58.44g/mol = 0.42779mol

No of moles Na+ ion = 0.42779mol

No of moles of Cl- ion = 0.42779mol

Total no of moles of ions = 2×0.42779mol =0.85558mol

Ionic molarity of the solution = (0.85558mol/50ml)×1000ml=17.11M

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