all calculations with units in your setups and the final answer for the followin

Question

all calculations with units in your setups and the final answer for the following. Show (1 pt.) A sample of nitrogen was collected of the (wet) gas sample was 745 torr, what was the pressure of the nitrogen gas alone? The vapor pressure of water vapor at 30.0 -31.8mm Hg. 2. over water at a temperature of 30.0 C. If the total pressure 3- (2 pts.) A sample of 0.0430 g magnesium, reacts with excess hydrochloric acid according to the following equation: The hydrogen gas is collected over water at 22 °C and a pressure of 749.2 mm Hg. The volume of hydrogen gas collected was 43.2 ml.. The barometric pressure is recorded as 749.2 mm of Hg. The vapor pressure of water vapor at 22 C-19.8 mm Hg. Calculate the percent purity of magnesium in the sample.

Explanation / Answer

(2)

Total pressure = 745 torr = 745 mm Hg

Pressure of water vapors = 31.8 mm Hg

So,

Pressure exterted by nitrogen gas alone = Total pressure-Vapor pressure of water = 745-31.8 = 713.2 mm Hg

Hope this helps !

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