In the laboratory you dissolve 16.5 g of calcium iodide in a volumetric flask an
ID: 1082980 • Letter: I
Question
In the laboratory you dissolve 16.5 g of calcium iodide in a volumetric flask and add water to a total volume of 250 mL.
What is the molarity of the solution? M.
What is the concentration of the calcium cation? M.
What is the concentration of the iodide anion? M.
In the laboratory you dissolve 22.5 g of sodium chloride in a volumetric flask and add water to a total volume of 500 mL.
What is the molarity of the solution? M.
What is the concentration of the sodium cation? M.
What is the concentration of the chloride anion? M.
Explanation / Answer
1.
mass of solute ( Calcium iodide) = 16.5 grams
molar mass of CaI2 = 293.9 gram/mole
volume of the solution= 250 ml
Molarity = mass of solute/molare mass of solute x1000/volume of solution in ml
Molarity = 16.5/293.9 x1000/250 = 0.2246M
Molarity of the solution = 0.2246M
CaI2------------------- Ca+2 + 2 I-
concentration of Ca+2 = 0.2246M
Concentration of I- = 2x0.2246 = 0.4492M
2.
mass of NaCl= 22.5 grams
molar mass of NaCl= 58.5 gram/mole
volume of the solution = 500 ml
Molarity of the solution = 22.5/58.5 x1000/500 = 0.769M
Molarity of the solution = 0.769M
NaCl --------------------- Na+ + Cl-
Concentration of Na+ = 0.769M
Concentration of Cl- = 0.769M
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