Practice Unit Test 1 Quiz chel Gentry: Attempt 1 Question 5 (10 points) Solve th

Question

Practice Unit Test 1 Quiz chel Gentry: Attempt 1 Question 5 (10 points) Solve the following problem Suppose you are running an experiment with a liquid the normal boiling point of which is 373 K at sea level. At a more elevated 43.9 kJ/mol, and R = 8.3145 J/(mol x K) Note: Your answer is assumed to be reduced to the highest power possible. Your Answer: altitude, the liquid boils at (2.01x10*2) K. What is the vapor pressure(in mm Hg) of the liquid at that altitude? Use DHvap x10 Answer units Save Question 6 (10 points)

Explanation / Answer

when boiling point (T1) = 373 K then vapor pressure pressure(P1) = 760 mm Hg.

when boiling point (T2) = 2.02 * 10^2 = 202 K and vapor pressure is P2 mm Hg

delta Hvap = 43.9 Kj / mole = 43900 J / mole.

we know,

ln (P2 / P1) = delta Hvap / R * (T2 - T1) / T1*T2

ln (P2 / 760) = 43900 / 8.3145 * (202 - 373) / 373 * 202

(P2 / 760) = 6.25 * 10^-6

P2 = 4.75 * 10^-3 mm Hg

vapour pressure of liquid is 4.75 * 10^-3 mm Hg.

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