Question 8 (1 point) The following reaction uses palladium, Pd, as a catalyst: C

Question

Question 8 (1 point)

The following reaction uses palladium, Pd, as a catalyst:

CO2(g)+H20(l) > H2CO3(l)

When palladium is absent, the reaction produces little product, even at long times. How does palladium influence the reaction?

Question 8 options:

The palladium reacts with the water.

The palladium lowers the activation energy.

The palladium purifies the carbon dioxide.

The palladium increases the reaction temperature.

Based on the following data, the reaction shown was found to have the rate law

rate=k[ICl][H2].

What are the units of the rate constant?

2ICl(g)+H2(g)2HCl(g)+I2(g)

Question 13 options:

mol/L/s

s1

mol2L2s1

L/mol/s

The palladium reacts with the water.

The palladium lowers the activation energy.

The palladium purifies the carbon dioxide.

The palladium increases the reaction temperature.

Explanation / Answer

8)
Catalyst lowers the activation energy and hence the reaction become faster
Here, Pd is catalyst.
So, it lowers the activation energy
Answer: The palladium lowers the activation energy.

9)
rate law is:
rate = k[ICl][H2]
put unit of all:
M/s =k * M* M
k = 1/(M.s)
= L/mol.s

Answer: L/mol/s

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