In the labo oratory a \"coffee cup\" calorimeter, or constant pressure calorimet

Question

In the labo oratory a "coffee cup" calorimeter, or constant pressure calorimeter, is frequently used to determine the specific heat of a solid, or to measure the energy of a solution phase reaction. me Since the cup itself can absorb energy, a separate experiment is needed to determine the heat capacity of the calorimeter. This is known as calibrating the calorimeter and the value determined is called the calorimeter constant One way to do this is to use a common metal of known heat capacity. In the laboratory a student heats 91.05 grams of zinc to 99.37 °C and then drops it into a cup containing 83.43 grams of water at 23.33 °C. She measures the final temperature to be 30.29 °C Metal Using the accepted value for the specific heat of zinc (See the References tool), calculate the calorimeter constant Calorimeter Constant = JOC

Explanation / Answer

heat lost by metal = heat gained by calorimeter+water

C = heat capacity of calorimeter = ?

   mass of zn metal *sm*DT1 = mass of water*sW*DT2 + C*DT2

specific heat of metal = Sm = 0.387 j/g.c

specific heat of water = Sw = 4.184 j/g.c

mass of zn metal = 91.05 g

mass of water = 83.43 g

(91.05*0.387*(99.37-30.29)) = (83.43*4.184*(30.29-23.33))+(C*(30.29-23.33))

C = heat capacity of calorimeter = 0.66 j/c

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