. 10.1g of KNO, (FM-101g/mol) are dissolved in 5000g point is in 500.0g of water

Question

. 10.1g of KNO, (FM-101g/mol) are dissolved in 5000g point is in 500.0g of water Oe 186) The freezing A. -0.37 B. 0.37 D. -0.74°C E. -1.49 6. For which of the following would you expect the solubility wo temperature. A. Alcohol B. Table salt C. Sugar D. Carbon dioxide E. Baking soda Open Ended To determine the molar mass of an unknown o camphor. First the pure camphor is melted to determine its freezing poins. Then the solution is created according to the data below. The graph shows the resulis of the experiment. organic solute is dissolved in 1. mcamphce 100g ke(camphor)-400C SOLVENT A. What is the freezing point of the pure solvent? B. What is the freezing point depression in the experiment? C. What is the molar mass of the solute? (Show calculations) Time

Explanation / Answer

Answer (5) moles of KNO3= mass/molar mass= 10.1/101= 0.1 moles

molality = moles of KNO3/mass of water in kg = 0.1/0.5= 0.2 m

we know that freezing point depression= i*kf*m

i= vant hoff factor for KNO3= 2 ; Kf for water = 1.86 C/m m=0.2 m

freezing point depression = 2*1.86*0.2= 0.744 degree celcius

freezing point will be 0-0.744= -0.744 degree celcius = 0.74 degree C

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