1. The third step in glycolysis is the conversion of fructose-6-phosphate to fru

Question

1. The third step in glycolysis is the conversion of fructose-6-phosphate to fructose-1,6- bisphosphate (F16BP) catalyzed by the enzyme PFK-1. This reaction is the "committed step" in glycolysis. Considering this, answer the following questions (please show all your work): A) If the reaction occurs as follows what will the Ksq be (1 point)? Assume R 8.315 J/mol and temp is 298K. fructose-6-phosphate + Pi F16BP Go'z +16.3 kJ/mol B) For the reaction above if we assume the [Pl to be 1.65mM what will the molar ratio of [F16BPl:[fructose-6-phosphate] be at equilibrium (I point)? C) Let's assume that the hexokinase reaction proceeds in the following manner as opposed to what we see in A) and B). Given this what is the new Keq (0.5 point)? fructose-6-phosphate + ATP Fi6BP+ ADP Gor=-14.2 kJ/mol

Explanation / Answer

1. The third step in glycolysis is the conversion of fructose-6-phosphate to fru

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