Often we mix the reactants together and measure one or all of the final concentr
ID: 1077865 • Letter: O
Question
Often we mix the reactants together and measure one or all of the final concentrations when the system reaches equilibrium. This means that at first, we do not know the changes in concentrations (the second row of our table) like we did in the previous example. We do know the stoichiometry of the changes, and this allows us to represent all of the concentration changes and their final equilibrium values using basic algebra Let's restart our reaction, this time starting with 1.00 M A and 1.50 M B Initial 0.00 1.00 M 1.50 M Some molar amount of compound A will react (we can call it x since it is not known). The stoichiometry then requires that 2x molar of B will also react and x molar C will be formed Change in - 2x M to Reach Equilibrium Using the same logic as in the previous example this allows us to fill in our table with algebraic representations of each of the concentrations. Equilibrium 1.00 x 1.50 2x If we can measure one of the equilibrium concentrations, we can use that value to solve for x and hence know all of the concentrations in the table Do You Understand? In our reaction, we started with 1.0 M A and 1.5 M B. If the equilibrium concentration of B = 0.500 M, What is the equilibrium concentration of A? What is the equilibrium concentration of C?Explanation / Answer
Often we mix the reactants together and measure one or all of the final concentr
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