Question 28 1 pts Using the information below, which of the following treatments

Question

Question 28 1 pts Using the information below, which of the following treatments might be highly effective for carbon monoxide poisoning, if started immediately? The oxygen in blood is carried by a lagge iron-containing protein called hemoglobin (Hb) Carbon monoxide also reacts widh he- moglobin. The equilibrium constant for the reaction of carbon monoxide with hemoglobin is approximasely 200 times larger than that for the reaction of oxygen with hemoglobia. From one all four of the oxygen molecules can be replaced with a carbon monoxide molecule. The following reaction shows only one oxygen molecule replaced with carbon monoxide. O Have the patient breathe pure gen. O Remove 250 mL of blood from the patient. O Decrease the pressure of the air that the patient is breathing. O Add additional iron to the patient's diet. Question 29 1 pts It is found that the value of the reaction quotient is 12 for a given reaction, whereas the equilibrium constant is 8.0. Which statement best describes how the system will respond? O Since Q

Explanation / Answer

The answer is

Have the patient breathe pure oxygen, you have the chemical equation the key here is to understand that you want to get the Hb(O2) to do this you need to shifts the equilibrium to the left to do this you have to remember lecheteliers principle which says that the system will look for equilibrium after a change, so if you increase the concentration of the compounds on the the right the equilibrium will shift to the left in this case increasing ammount of oxygen by breathing pure oxygen will force the CO to unbind from hemoglobin

Question 2

aA + bB cC + dD

Equilibrium constant is the relationship of products and reactants expressed like this

K = [A]a [B]b / ( [C]c[D]d )

Q is a very similar expression Q is the relationship at any point

at equilibrium Q is equal to K so

Q is 12 this means that the reaction favors the products too much vs the equilibrium

the K equilibrium is 8 so the system will look for equilibrium by reducing the ammount of products and increasing the ammount of reactants so

Q > K, the reverse reaction is favored and the equilibrium shifts to the left.

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