assessment id. \" 19854-1une id-,24520, 1&content;,d .,670962_1&oeston; nminenog

Question

assessment id. " 19854-1une id-,24520, 1&content;,d .,670962_1&oeston; nminenoggt Muple Atompts This test allows 3 ahempts. This is atempt number 1 Force Completion This lest can be saved and nesumed laler Question Completion Stats Moving to another queston "a savensresponse. ) Question 1 points Aburn patent has achiorideo, dhoerey of 135nEgHow mary manors of a 375%Nmous chi ride solution dr02-m.w 127)th udd be admatured to replace the a 567 mt b 22.86 ml 6.39 86 ml Chapter 20 Practi ppta to search 5 6 8 9

Explanation / Answer

Ans : b) 22.86 mL

Let the volume of solution be 100 mL

So mass of FeCl2 in solution = (37.5 x 100) / 100 = 37.5 g

Number of moles of FeCl2 = mass / molar mass

= 37.5 / 127

= 0.295 mol

Number of equivalents of Cl = 2 x 0.295

= 0.59 eq

So if 100 mL of solution has 0.59 Eq of Cl ion

Then volume of solution having 135mEq will be :

= ( 135 x 10-3x 100) / 0.59

= 22.86 mL

=

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