1. What quantity of sulfur dioxide, SO2 (64.0 g\'mole), is produced when 245 g o
ID: 1075479 • Letter: 1
Question
1. What quantity of sulfur dioxide, SO2 (64.0 g'mole), is produced when 245 g of sulfuric acid, H2S04 (98.0 g/mole) reacts completely with zinc metal? Zn° + 2 H2SO4 ZnSO4 + SO2 + 2H2O 2. Consider the following balanced equation: CMO + s ode) 3 cole) + 4 Hoe) What mass of CO, is formed when 100 grams of CHe react? 3. Calculate the number of grams of nitrogen dioxide that are produced from4 moles of nitric oxide. 4. Calculate the mass of oxygen produced from the decomposition of 75.0 g of potassium chlorate. 2KCIOds) 2KCI(s) + 302(g) 5. . Calculate the mass of silver needed to react with chlorine to produce 84 g of silver chloride 6. 2Al(s) + 6HCI(aq) 2AICI3(aq) + 3H2(g) Accordi 2.19 mol of hydrochloric acid? ng to the equation above, how many grams of aluminum are needed to completely react with 7. Sulfur dioxide will react with water to form sulfurous acid (see balanced so2(g) + H2O() H2SO3() What mass of sulfur dioxide is needed to prepare 27.86 g of H2SO3l)? equation below).Explanation / Answer
Solved the first four problem as per Chegg guidelines, post multiple question to get the remaining answers
1)
Reaction is
Zn + 2H2SO4 ---- ZnSO4 + SO2 + 2H2O
number of moles of sulfuric acid = mass/molar mass = 245/98 = 2.5 moles
2 moles of sulphuric acid produce one mole of SO2
moles of SO2 produced = 2.5/2 = 1.25
Mass of SO2 produced = number of moles * molar mass = 1.25 mol * 64 gm/mol = 80 grams
2)
C3H8 + 5O2 ------ 3CO2 + 4H2O
number of moles of C3H8 = Mass/molar mass = 100/(3*12+8*1) = 100/44 = 2.2727 moles
Moles of CO2 produced = 3 * 2.2727 = 6.818 moles
Mass of CO2 produced = number of moles * molar mass = 6.818 mol * 44 gm/mol = 300 grams
3)
1 mole of NO gives 1 moles of NO2
Number of moles of NO2 = 4
Molar mass of NO2 = 14 + 2 * 16 = 46 gm/mol
Mass of NO2 produced = number of moles * molar mass = 4 mol * 46 gm/mol = 184 gm/mol
4)
2KClO3 ----- 2KCl + 3O2
molar mass of KClO3 = 122.5 gm/mol
Number of moles of KClO3 = mass/molar mass = 75/122.5 = 0.6122 moles
Moles of O2 produced = 3/2 * 0.6122 = 0.9183
Mass of O2 produced = number of moles * molar mass = 0.9183 mol * 32 gm/mol = 29.3856 gms
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