4. To find the Ce4+ content of a solid, 4.37 g were dissolved and treated with e

Question

4. To find the Ce4+ content of a solid, 4.37 g were dissolved and treated with excess iodate to precipitate Ce(IO3)4. The precipitate was collected, washed well, dried, and ignited to produce 0.104 g or CeO2 (FM 172.114). What was the weight percent of Ce in the original solid? 4. To find the Ce4+ content of a solid, 4.37 g were dissolved and treated with excess iodate to precipitate Ce(IO3)4. The precipitate was collected, washed well, dried, and ignited to produce 0.104 g or CeO2 (FM 172.114). What was the weight percent of Ce in the original solid?

Explanation / Answer

Mass of CeO2 = 0.104 g

Moles of CeO2 = mass/molecular weight

= 0.104 g/172.115g/mol

= 6.077 x 10^-4 moles

1 mol Ce produces = 1 mol CeO2

6.077 x 10^-4 moles Ce produces = 6.077 x 10^-4 moles CeO2

Mass of Ce in CeO2 = 140.1 g/mol X 6.077 x 10^-4 moles

= 0.0851 g

% Ce = mass of Ce x 100/mass of sample

= 0.0851 g *100/4.37 g

= 1.94%

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