Pre-Lab Questions 1. Iodine (I2) is only sparingly soluble in water (Equation 2)

Question

Pre-Lab Questions 1. Iodine (I2) is only sparingly soluble in water (Equation 2). In the presence of potassium iodide, a source of iodide (I-) ions, iodine reacts to form triiodide (I3) ions (Equation 3). 12(s) 12(aq) 12(aq) + I-(aq) 13(aq) Use LeChâtelier's Principle to explain why the solubility of iodine in water increases as Equation 2 Equation 3 the concentration of potassium iodide increases. 2. Dissolving ammonium chloride in water is an endothermic reaction (Equation 4). Use LeChâtelier's Principle to predict whether ammonium chloride will be more soluble in hot or cold water. NH4Cl(s) + heat NH4+(aq) + Cl-(aq) Equation 4

Explanation / Answer

1) Le-chatelier principle states that if any changes take place at equilibrium, reaction goes in that direction to minimise that effect of change.so if reactants are introduced then reactio would go toward right so as to minimise concentration of reactant.

2) for endothermic reaction ,heat needs to be absorbed to catalyse the reaction.so if temerature of water is high then reaction would g very fastly...

nh4cl more soluble in hot water...

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