Suppose a 250. mL flask is filled with 1.2 moles of NO2 and 1.6 moles of NO. Che

Question

Suppose a 250. mL flask is filled with 1.2 moles of NO2 and 1.6 moles of NO. Check sig figs. Please show me step by step. Suppose a 250. ml. flask is filled with 1.2 mol of NO2 and 1.6 mol of NO. This reaction becomes possible: 2N02(g)-2NO(g) +02(g) Complete the table below, so thnar r lists the intial molanity af each compound, the change in molarity of each compound due to the reaction, and the Use x to stand for the unknown change in the molarity of O2. You can leave out the M symbol for molarity NO2 No 0, initial change

Explanation / Answer

Molarity of NO2 = Number of moles of NO2/Volume of solution in L = 1.2/0.250 = 4.8M

Molarity of NO = Number of moles of NO/Volume of solution in L = 1.6/0.250 = 6.4M

Initial molarity of O2 will be 0

Now 2 moles of NO2 will give 2 moles of NO and 1 mole of O2, since change in O2 is given as x, hence the change in NO2 will be (2x) but since it is reactant it will be negative an positive for NO

so the table will be

[NO2] [NO] O2 Initial 4.8 6.4 0 Change -2x 2x x Equilibrium 4.8-2x 6.4+2x x

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