Second lonization Energy Ionization Energy Ionization Energy (kJ mol-\') 2.300 4

Question

Second lonization Energy Ionization Energy Ionization Energy (kJ mol-') 2.300 4.560 1.450 2.250 First Third (kJ mol-) 3.820 6,910 7.730 (kJ mol-1) 1.25 Element 1 Element 2 Element 3 Element4 496 738 1.000 3.360 The table above shows the first three ionization energies for atoms of four elements from the third period of the periodic table. The elements are numbered randomly. Use the information in the table to answer the following questions. (a) Which element is most metallic in character? Explain your reasoning. (b) Identify element 3. Explain your reasoning. (c) Write the complete electron configuration for an atom of element 3. (d) What is the expected oxidation state for the most common ion of element 2? (e) What is the chemical symbol for element 2? (f) A neutral atom of which of the four elements has the smallest radius?

Explanation / Answer

(a) Element 2 should have most metallic character as it possess least ionization energy

(b) It should be magnesium as it is relatively easy to remove first 2 electrons from outer shell and difficult to remove inner core electrons and hence higher ionization energy

(c) 1s22s22p63s2

(d) It should be +1 as the ionization energy to remove 2nd electron is vergy high

(e) It should be Na

(f) It should be element 1 as when we go right in a period,ionization energy increases

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