9 Match 0.13910.1599101 97.8 35.45 64.55 59 gl 0.7210.72g10.72 gl 0.56110.561g10

Question

9 Match 0.13910.1599101 97.8 35.45 64.55 59 gl 0.7210.72g10.72 gl 0.56110.561g10.5 61 gl 3.1213.12g13.12 9l Q: How many grams of dextrose must be added to this formulation? Drug G (E-value 0.244) 650 mg Water qs ad value 0.18) qs ad isotonic guided questions: -What is the NaCI equivalent of drug G7,-1-g (3 sig fig)-How many grams of NaCl in a pure isotonic solution of 80ml?-2-g-How many grams of NaCl would have to be added to make the formulation isotonic? 3 g -How dextrose is added instead of NaCl, how many grams of dextrose would have to be added to make the formulation isotonic? 4g (3 sig fig) 80 ml Dextrose (E B1: 0.15910.159g10.159 gl B2:0.7210.72g10.72 g B3: 0.56110.561g10.561 gl B4: 3.1213.12g13.12 gl

Explanation / Answer

1. The NaCl equivalent of drug G = amount of drug G * Correspond E-value = 0.65 g * 0.244 = 0.159 g

2. The amount of NaCl in a pure isotonic solution of 80 mL = (0.9/100) * total volume = (0.9/100) * 80 = 0.72 g (since standard: 0.9% w/v NaCl at isotonic)

3. The amount of NaCl that should be added to make the formulation isotonic = 0.72 - 0.159 = 0.561 g

4. Therefore, the amount of dextrose that should be added to make the formulation isotonic = 0.561/0.18 = 3.12 g

Related Questions

Navigate

• Browse (All)
• Browse 9
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.