HONORS CHEMISTRY LIMITING REACTANTS AND PERCENT YIELD Name: Calculate the theore
ID: 1074226 • Letter: H
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HONORS CHEMISTRY LIMITING REACTANTS AND PERCENT YIELD Name: Calculate the theoretical yield of product (in moles) for each initial omount of reactant Manganese metal reacts with oxygen gas to yield Manganese (TV) oxide 3 mol Manganese, 3 mol of oxygen a. b. 4 mol Manganese, 7 mol of oxygen 27.5 mol Manganese, 43.8 mol of oxygen c. Iron (II) sulfide reacts with hydrochloric acid. The reaction mixture initially contains 0.223 mol of Iron (II) sulfide and 0.652 mol of hydrochloric acid. Once the reaction has reached completion, what amount (in mol) of the excess reactant is left? Titanium metal reacts with fluorine. Calculate the theoretical yield (in grams) for each amount of reactants a. 5.0 g of Titanium, 5.0 g of fluorine b. 2.4 g of Titanium, 1.6 g of fluorine c. 0.233 kg of Titanium, 0.288 kg of fluorine Magnesium oxide can be made by heating magnesium metal. When 10.0 g of Mg reacts with 10.5 g of oxygen 11.9 g of magnesium oxide is collected. Determine the limiting reactant, theoretical yield and percent yield for the reaction. Many computer chips are manufactured from silicon, which occurs in nature as silicon dioxide. When silicon dioxide is heated to melting, it reacts with solid carbon to for liquid silicon and carbon monoxide. In an industrial preparation of 5. silicon, 155.8 kg of silicon dioxide reacts with 78.3 kg of carbon to produce 66.1 kg of silicon. Determine the limiting reactant, theoretical yield and percent yield for the reaction.Explanation / Answer
2Mg + O2 -> 2MgO
Molar mass of Magnesium: 24.035g/mol
Molar mass of Oxygen: 31.998 g/mol
Moles of magnesium: 10.0g/24.035g/mol = 0.416 mol
Moles of oxygen: 10.5/31.998g/mol = 0.328 mol
oxygen is the limiting reactant.moles of mgo= moles of mg
theoretical yield- moles of mgo * mass of mgo
0.416 * 40.304= 16.76g
percentage yield- actual/theoretical * 100
11.9 / 16.76 * 100= 71%
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